Answer:
Step-by-step explanation:
The point-slope form of an equation of a line:
[tex]y-y_1=m(x-x_1)[/tex]
m - slope
The formula of a slope:
[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]
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We have the slope m = -6 and the point (-9, -3).
Substitute:
[tex]y-(-3)=-6(x-(-9))\\\\y+3=-6(x+9)[/tex]
Convert to the slope-intercept form (y = mx + b):
[tex]y+3=-6(x+9)[/tex] use the distributive property
[tex]y+3=-6x-54[/tex] subtract 3 from both sides
[tex]y=-6x-57[/tex]
