The height, h, in feet of a golf ball above the ground after being hit into the air is given by the equation, h = -16t 2 + 64t, where t is the number of seconds elapsed since the ball was hit. How many seconds does it take for the golf ball to hit the ground?

Question

contestada

Respuesta :

luisejr77 luisejr77 · Answer 1 · 2019-06-13T19:53:10+02:00

Answer: 4 seconds

Step-by-step explanation:

We have the equation that models the height of the golf ball in feet after being hit.

When the ball reaches the ground its height is equal to zero.

Then to solve this problem you must equal h to zero and solve the equation for the variable t

[tex]h = -16t^2 + 64t=0[/tex]

[tex]-16t^2 + 64t=0[/tex]

Take 16t as a common factor

[tex]-16t(t - 4)=0[/tex]

The equation is equal to zero when t = 0 and when t = 4

t = 0 is at the instant in which the ball has just been hit and t = 4 seconds is the instant in which the ball touches the ground.

Then the answer is t=4 seconds