Answer:
[tex]\large\boxed{(3a+2)(4a^2-2a+9)=12a^3+2a^2+23a+18}[/tex]
Step-by-step explanation:
[tex](3a+2)(4a^2-2a+9)\qquad\text{use FOIL:}\ (a+b)(c+d)=ac+ad+bc+bd\\\\=(3a)(4a^2)+(3a)(-2a)+(3a)(9)+(2)(4a^2)+(2)(-2a)+(2)(9)\\\\=12a^3-6a^2+27a+8a^2-4a+18\qquad\text{combine like terms}\\\\=12a^3+(-6a^2+8a^2)+(27a-4a)+18\\\\=12a^3+2a^2+23a+18[/tex]
