Answer: (0, -1 [tex]\frac{2}{3}[/tex]), (1, -1), (2, 1)
Step-by-step explanation:
Set the exponent equal to zero - that is your anchor point.
Then choose an x-value less than and greater than the anchor point.
[tex]\left\begin{array}{c|c|l}&\underline{\quad x\quad }&\underline{\qquad \qquad f(x)\qquad \qquad \qquad \quad }\\\text{less than anchor}&0&3^{0-1}-2=3^{-1}-2=\frac{1}{3}-2 = -1\frac{2}{3}}\\\\anchor\ point&1&3^{1-1}-2=3^{0}-2=1-2 = -1}\\\\\text{greater than anchor}&2&3^{2-1}-2=3^{1}-2=3-2 = 1}\end{array}\right[/tex]
