The Perimeter of rectangle DEFG is 120, ED=X, and FE=4x. What is the value of x?
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Perimeter=120
ED=x (length)
FE=4x (breadth)
Perimeter of rectangle= 2(l+b)
Given,
2(x+4x)=120
2x+8x=120
10x=120
x=120÷10
x=12
Therefore, value of x is 12
Answer: 12
Step-by-step explanation:
You are given that perimeter = 120, length (FE) = 4x, and width (ED) = x
P = 2L + 2w (P = perimeter, L = length, w = width)
120 = 2(4x) + 2(x)
120 = 8x + 2x
120 = 10x
÷10 ÷10
12 = x