Answer:
1. x=±4
2. t=±9
3. r=±10
4. x=±12
5. s=±5
Step-by-step explanation:
1. x^2 = 16
Taking square root on both sides
[tex]\sqrt{x^2}=\sqrt{16}\\\sqrt{x^2}=\sqrt{(4)^2}\\[/tex]
x=±4
2. t^2=81
Taking square root on both sides
[tex]\sqrt{t^2}=\sqrt{81}\\\sqrt{t^2}=\sqrt{(9)^2}[/tex]
t=±9
3. r^2-100=0
[tex]r^{2}-100=0\\r^2 =100\\Taking\ Square\ root\ on\ both\ sides\\\sqrt{r^2}=\sqrt{100}\\\sqrt{r^2}=\sqrt{(10)^2}[/tex]
r=±10
4. x²-144=0
x²=144
Taking square root on both sides
[tex]\sqrt{x^2}=\sqrt{144}\\\sqrt{x^2}=\sqrt{(12)^2}[/tex]
x=±12
5. 2s²=50
[tex]\frac{2s^2}{2} =\frac{50}{2}\\s^2=25\\Taking\ Square\ root\ on\ both\ sides\\\sqrt{s^2}=\sqrt{25}\\\sqrt{s^2}=\sqrt{(5)^2}[/tex]
s=±5 ..
Answer:
[tex]1.+4,-4\\2. +9,-9\\3. +10,-10\\4. +12, -12\\5. +5, -5[/tex]
Step-by-step explanation:
IN order to solve the quadratic equations you just have to solve the square root of the numeric part of the equation:
[tex]x^{2} =16\\x=\sqrt{16}\\ x= +4, -4[/tex]
[tex]t^{2} =16\\t=\sqrt{81}\\ x= +9, -9[/tex]
[tex]r^{2} =100\\r=\sqrt{100}\\ x= +10, -10[/tex]
[tex]x^{2} -144=0\\x=\sqrt{144}\\ x= +12, -12[/tex]
[tex]2s^{2}=50\\s^{2}=\frac{50}{2} \\s=\sqrt{25}\\ s= +5, -5[/tex]
Just remember that the solution for any square root will always be a negative and a positive number.
