Suppose you apply a force of "20 N to a 0.25-meter-long wrench attached to a bolt in a direction perpendicular to the bolt. Determine the magnitude of the torque when the force is applied at an angle of 120degrees°" to the wrench.

Torque is defined as the force that produces rotation around the axis of an object. Torque is also known as the moment of force. It's S.I unit is Nm.

Formula of torque is:

τ= rxF(sinθ)

Given Data:

Force = 20 N

r = 0.25 m

θ = 120°

Solution:

τ= rxF(sinθ)

= 0.25 x 20 (sin 120)

= 2.903 Nm

Thus, the total torque applied on the wrench is 2.903 Nm.

Suppose you apply a force of "20 N to a 0.25​-meter-long wrench attached to a bolt in a direction perpendicular to the bolt. Determine the magnitude of the torque when the force is applied at an angle of 120degrees°" to the wrench.

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Suppose you apply a force of "20 N to a 0.25-meter-long wrench attached to a bolt in a direction perpendicular to the bolt. Determine the magnitude of the torque when the force is applied at an angle of 120degrees°" to the wrench.