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Enough of a monoprotic acid is dissolved in water to produce a 0.0142 M solution. The pH of the resulting solution is 2.58. Calculate the Ka for the acid.

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drpelezo

Answer:

Ka = 4.9 x 10ˉ⁴

Explanation:

HOAc    ⇄    H⁺    +    OAcˉ

Ka = [H⁺][OAcˉ]/[HOAc]

Given pH = 2.58 => [H⁺] = [OAcˉ] = 10ˉ²∙⁵⁸ = 2.63 x 10ˉ³M

Ka = (2.63 x 10ˉ³)²/(0.0142) = 4.9 x 10ˉ⁴

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