Answer:
The distance from B to B’ is [tex]5\ units[/tex]
Step-by-step explanation:
we know that
In a translation the shape and dimensions of the figure are not going to change.
therefore
AA'=BB'=CC'=DD'
Find the distance AA'
the formula to calculate the distance between two points is equal to
[tex]d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}[/tex]
[tex]A(1,5)\\A'(-2.1)[/tex]
substitute the values
[tex]AA'=\sqrt{(1-5)^{2}+(-2-1)^{2}}[/tex]
[tex]AA'=\sqrt{(-4)^{2}+(-3)^{2}}[/tex]
[tex]AA'=\sqrt{25}[/tex]
[tex]AA'=5\ units[/tex]
therefore
[tex]BB'=5\ units[/tex]
