Answer:
[tex]6.33\cdot 10^{-7} m[/tex]
Explanation:
The condition for the first minimum (= first dark fringe) in the interference pattern produced by diffraction from a double slit is
[tex]d sin \theta = \frac{\lambda}{2}[/tex]
where
[tex]d=0.33 mm = 0.33\cdot 10^{-3}m[/tex] is the separation between the slits
[tex]\theta=0.055^{\circ}[/tex] is the angle of the first minimum
[tex]\lambda[/tex] is the wavelength
Solving the equation for the wavelength, we find
[tex]\lambda = 2 d sin \theta = 2(0.33\cdot 10^{-3} m)sin 0.055^{\circ}=6.33\cdot 10^{-7} m[/tex]
