Answer:
9.2 N, with significant figure rounding (2 s.f.)
Explanation:
This problem can be solved using momentum. The following equation relates momentum (mass & velocity) with force and time:
Note that where v is the final velocity and v₀ is the initial velocity. Δv just means change in velocity.
Mass of the egg is 150 g, but we need to convert to kilograms if we want to use Newtons as a unit. 150 g is equal to 0.15 kg. since 1000 g = 1kg.
m = 0.15 kg
The dropped from 3.0 meters is irrelevant as the question tells us the initial velocity of the egg: 4.4 m/s before it hits the ground.
v₀ = 4.4 m/s [down]
When it comes to a stop, the egg will have a velocity of 0.
v = 0 m/s
The time it takes for the egg to stop is 0.072 seconds.
Δt = 0.072 s
Therefore, if down is positive, then
We round to two significant figures since every quantity has two sig. figs.
We only care about the magnitude, not direction. The answer is 9.2 N.
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5.0
The magnitude of force that the ground exerted on the egg is 9.2N
The change in momentum is equal to the product of impact force applied while colliding and time for that impact.
F. t = m (Vf -Vi)
where, Vf is the final velocity and Vi is the initial velocity.
Given, mass of the egg is 150 g, m = 0.15 kg
The egg is dropped from 3.0 meters and the initial velocity v₀ = 4.4 m/s [down]
When egg strikes the ground, the egg will move with v = 0 m/s
The time taken for the egg to stop is Δt = 0.072 s
Substitute the values into the expression, we get
F x 0.072 = 0.15 x (0 - 4.4)
F = 9.16N
Thus the magnitude of force is 9.2 N.
Learn more about impulse.
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