Answer:
[tex]2\sqrt{2}[/tex]
Step-by-step explanation:
We are required to simplify the following expression;
[tex]\frac{\sqrt{8y} }{\sqrt{y} }[/tex]
Using the properties of radicals;
[tex]\frac{\sqrt{a} }{\sqrt{b}}=\sqrt{\frac{a}{b} }[/tex]
The expression can be re-written as;
[tex]\sqrt{\frac{8y}{y}}=\sqrt{8}[/tex]
Now;
[tex]\sqrt{8}=\sqrt{4*2}=\sqrt{4}*\sqrt{2}\\ \\2\sqrt{2}[/tex]
