contestada

During takeoff, an airplane climbs with a speed of 150 m/s at an angle of 45 degrees above the horizontal. The speed and direction of the airplane constitute a vector quantity known as the velocity. The sun is shining directly overhead. How fast is the shadow of the plane moving along the ground

Respuesta :

skyluke89

Answer:

106.1 m/s

Explanation:

The shadow of the plane is moving at the same velocity as the horizontal component of the airplane's velocity.

The horizontal component of the airplane's velocity is

[tex]v_x = v cos \theta[/tex]

where

v = 150 m/s is the velocity of the airplane

[tex]\theta=45^{\circ}[/tex] is the angle between the airplane's velocity and the horizontal

Substituting,

[tex]v_x = (150 m/s) cos 45^{\circ} = 106.1 m/s[/tex]

So, the shadow is moving at 106.1 m/s as well.

Otras preguntas