Answer:
Oxidation state of N in (NH₄) is (-3).
Oxidation state of N in (NO₂) is (+3).
Explanation:
NH₄NO₂ → NH₄⁺ + NO₂⁻.
NH₄⁺:
The total oxidation state of NH₄⁺ is (+1).
The oxidation state of H is known to be (+1).
∴ Oxidation state of N + 4(oxidation state of H) = +1.
∴ Oxidation state of N + 4(+1) = +1.
∴ Oxidation state of N = +1 - 4 = -3.
NO₂⁻:
The total oxidation state of NO₂⁻ is (-1).
The oxidation state of O is known to be (-2).
∴ Oxidation state of N + 2(oxidation state of O) = -1.
∴ Oxidation state of N + 2(-2) = -1.
∴ Oxidation state of N - 4 = -1.
∴ Oxidation state of N = -1 + 4 = +3.
Two oxidation states of nitrogen in NH₄NO₂ is +3 & -3.
Oxidation state of any atom tells about the no. of electrons gain or looses from that atom.
NH₄NO₂ is dissociates as:
NH₄NO₂ → NH₄⁺ + NO₂⁻
Oxygen state of nitrogen in NH₄⁺ can be calculated as:
x + 4(1) = 1
x = 1 - 4 = -3
In NH₄⁺, oxidation state of hydrogen is +1 & whole charge on the ion is also +1.
Oxygen state of nitrogen in NO₂⁻ can be calculated as:
x + 2(-2) = -1
x = -1 + 4 = 3
In NO₂⁻, oxidation state of oxygen is -2 & whole charge on the ion is -1.
Hence, -3 & +3 are the oxidation states of nitrogen.
To learn more about oxygen state, visit the below link:
https://brainly.com/question/8990767
