Answer:
Part a) The elevation of the road is [tex]6\°[/tex]
Part b) The rise is [tex]0.2\ km[/tex]
Step-by-step explanation:
Part a) What is the elevation of the road to the nearest degree?
Let
y-----> the rise of the road ( vertical distance)
x ----> the run of the road (horizontal distance)
we have
y/x=1/10
we know that
The ratio y/x is equal to the tangent of the angle of the elevation of the road
Let
[tex]\theta[/tex] ----> angle of the elevation of the road
[tex]tan(\theta)=y/x[/tex]
[tex]tan(\theta)=1/10[/tex]
[tex]\theta=arctan(1/10)=6\°[/tex]
Part b) If the road is two km long, how much does it rise?
using proportion
[tex]1/10=y/2[/tex]
[tex]y=2/10=0.2\ km[/tex]
