Answer:
[tex]43.2^{\circ}C[/tex]
Explanation:
The change in temperature of the sample of alcohol is given by:
[tex]\Delta T=\frac{Q}{mC_s}[/tex]
where
Q = 890 J is the amount of heat provided to the sample
m = 16.6 g is the mass of the sample
[tex]C_s = 2.47 J/gC[/tex] is the specific heat of alcohol
Solving the equation,
[tex]\Delta T = \frac{890 J}{(16.6 g)(2.47 J/gC)}=21.7^{\circ}C[/tex]
And since the initial temperature was
[tex]T_i = 21.5^{\circ}C[/tex]
the final temperature is
[tex]T_f = T_i + \Delta T=21.5^{\circ}C + 21.7^{\circ}C=43.2^{\circ}C[/tex]
