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A theater group made appearances in two cities. The hotel charge before tax in the second city was $1000 higher than in the first. The tax in the first city was 3%, and the tax in the second city was 8%. The total hotel tax paid for the two cities was $410. How much was the hotel charge in each city before tax?

Respuesta :

Answer:

Let x = the charge in 1st city before taxes

Let y = the charge in 2nd city before taxes

 

 

Set up equation before taxes.

 

y = x - 1500        eq1

 

 

Set up equation for total tax paid.

 

0.065x + 0.06y = 378.75         eq2

 

 

Substitute eq1 into eq2.

 

0.065x + 0.06(x - 1500) = 378.75

0.065x + 0.06x - 90 = 378.75

0.125x - 90 = 378.75

0.125x = 468.75

       x = 3750

 

Substitute this value of x into eq1.

 

y = 3750 - 1500

y = 2250

 

 

The hotel charge in city one is $3750 and the hotel charge in city two is $2250.

Step-by-step explanation:

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