Answer:
4845 ways
Step-by-step explanation:
To solve this problem we use the formula of combinations
[tex]nCr=\frac{n!}{r!(n-r)!}[/tex]
Where n is the total number of students that can be chosen and you choose r from them.
So
[tex]n = 20\\r = 4[/tex]
Note that in this case the order in which the 4 students are chosen does not matter.
Then
[tex]20C4=\frac{20!}{4!(20-4)!}[/tex]
[tex]20C4=\frac{20!}{4!*16!}=4845\ ways[/tex]
