Look at the figure:

An image of a right triangle is shown with an angle labeled x.

If tan x° = 11 divided by r and cos x° = r divided by s, what is the value of sin x°?

sin x° = s divided by 11
sin x° = 11 divided by s
sin x° = 11r
sin x° = 11s

Respuesta :

Answer:

sin(x°) = 11/s

Step-by-step explanation:

The tangent is the ratio of sine to cosine, so ...

tan(x°) = sin(x°)/cos(x°)

Multiplying by cos(x°) gives ...

sin(x°) = cos(x°)·tan(x°) = (r/s)·(11/r)

sin(x°) = 11/s

Answer:

sin x° = 11 divided by s

Step-by-step explanation:

Given,

tan x° = 11 divided by r

[tex]\implies tan x^{\circ}=\frac{11}{r}[/tex]

Also, cos x° = r divided by s

[tex]\implies cos x^{\circ}=\frac{r}{s}[/tex]

We know that,

[tex]\frac{sinx^{\circ}}{cos x^{\circ}}=tan x^{\circ}[/tex]

[tex]\implies sinx^{\circ}= tan x^{\circ}\times cos x^{\circ}[/tex]  ( by cross multiplication )

By substituting the values,

[tex]sin x^{\circ}=\frac{11}{r}\times \frac{r}{s}=\frac{11r}{rs}=\frac{11}{s}[/tex]

⇒ sin x° = 11 divided by s