Answer:
see explanation
Step-by-step explanation:
1
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
here m = - [tex]\frac{1}{4}[/tex], hence
y = - [tex]\frac{1}{4}[/tex] x + c ← is the partial equation
To find c substitute (8, - 1) into the partial equation
- 1 = - 2 + c ⇒ c = - 1 + 2 = 1
y = - [tex]\frac{1}{4}[/tex] x + 1 ← in slope- intercept form
2
The equation of a line in point- slope form is
y - b = m(x - a)
where m is the slope and (a, b) a point on the line
here m = - 1 and (a, b) = (- 2, 5), hence
y - 5 = - (x - (- 2)), that is
y - 5 = - (x + 2)