Answer:
x = 1 + √74/6 or x = 1 - √74/6
Step-by-step explanation:
Points to remember
Zeros of a quadratic equation ax² + bx + c = 0
x = [-b ± √(b² - 4ac)]/2a
To find the zeros of given quadratic equation
It is given that,
6x² +12x - 7 = 0
Here a = 6, b = -12 and c = -7
x = [-b ± √(b² - 4ac)]/2a
= [-12 ± √(12² - 4*6*(-7))]/2*6
= [12 ± √(144 +168 )]/12
= [12 ± √312]/12
= [12 ± 2√74]/12
= 1 ± √74/6
x = 1 + √74/6 and x = 1 - √74/6
