Hello!
The answer is:
The voltage of the source is 8.40 Volts.
Why?
To solve the problem, we need to use the Ohm's Law equation, which states that:
[tex]Voltage(Volts)=Current(Amps)*Resistance(Ohm)[/tex]
From the statement we know that:
[tex]Resistance=2.21\Omega\\Power=32W\\Current=3.8A[/tex]
Now, substituting and calculating we have:
[tex]Voltage(Volts)=Current(Amps)*Resistance(Ohm)[/tex]
[tex]Voltage(Volts)=3.8A*2.21\Omega=8.40V[/tex]
Hence, we have that the voltage of the source is 8.40 Volts.
Have a nice day!
