Answer:
1/(x+3)+7/(x+2)
Step-by-step explanation:
I'm assuming the full numerator is (8x+23)... and by making that assumption I'm assumed the fraction was (8x+23)/[(x+3)(x+2)].
(8x+23)/[(x+3)(x+2)]=A/(x+3)+B/(x+2)
8x+23=A(x+2)+B(x+3) I multiply both sides by (x+3)(x+2)
Set x to -2 that gives -16+23=B so this means B=7
Set x to -3 instead that gives -24+23=A(-1) so this means A=1
So (8x+23)/[(x+3)(x+2)]=1/(x+3)+7/(x+2)
