Answer:
The correct application of the quadratic formula is:
[tex]x=\dfrac{9\pm \sqrt{(-9)^2-4(6)(22)}}{2(6)}[/tex]
Step-by-step explanation:
The quadratic equation is given by:
[tex]y=6x^2-9x+22[/tex]
We know that the solution of the quadratic equation:
[tex]y=ax^2+bx+c[/tex]
is given by:
[tex]y=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]
Here we have:
[tex]a=6[/tex]
[tex]b=-9[/tex]
and
[tex]c=22[/tex]
Hence, the quadratic formula is given by:
[tex]x=\dfrac{-(-9)\pm \sqrt{(-9)^2-4\cdot (6)\cdot (22)}}{2\cdot (6)}[/tex]
i.e.
[tex]x=\dfrac{9\pm \sqrt{(-9)^2-4(6)(22)}}{2(6)}[/tex]
