Answer:
The Experimental Probability of the spinner stopping on Section A is 1/3.
Step-by-step explanation:
Number of time spinner landed on section A = 4
Number of time spinner landed on section B = 5
Number of time spinner landed on section C = 2
Number of time spinner landed on section D = 1
Total Number of spins = 12
[tex]Probability=\frac{Number\:of\;Favorable\:outcome}{Number\:of\:total\;outcome}=\frac{4}{12}=\frac{1}{3}[/tex]
Therefore, The Experimental Probability of the spinner stopping on Section A is 1/3.