In triangle STU, UT=5 and angleS=21. Find SU to the nearest tenth
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The answer is:
The second option,
[tex]SU=13.02=13[/tex]
We are working with a right triangle, it means that we can use the following trigonometric property:
[tex]Tan(\alpha)=\frac{Opposite}{Adjacent}[/tex]
Which applied to our problem, will be:
[tex]Tan(\alpha)=\frac{TU}{SU}[/tex]
We are given:
m∠S, equal to 21°
The side TU (opposite) equal to 5 units.
So, substituting and calculating we have:
[tex]SU=\frac{TU}{Tan(\alpha)}[/tex]
[tex]SU=\frac{5units}{Tan(21\°)}[/tex]
[tex]SU=13.02=13[/tex]
Hence, the answer is the second option
[tex]SU=13.02=13[/tex]
Have a nice day!
Answer:
13.0
Step-by-step explanation:
The given angle is m<S=21.
The given side length UT=5 units.
This side length is opposite to the given angle.
Since we want to find SU, the adjacent side; we use the tangent ratio to obtain;
[tex]\tan 21\degree=\frac{opposite}{adjacent}[/tex]
[tex]\tan 21\degree=\frac{5}{SU}[/tex]
This implies that;
[tex]SU=\frac{5}{\tan 21\degree}[/tex]
Therefore SU=13.025
The nearest tenth
SU=13.0