The rabbit population of Springfield, Ohio was 144,000 in 2016. It is expected to decrease by about 7.2% per year. Write an exponential decay function, P(t), and use it to approximate the population in 2036.

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The answer is:

In 2036 there will be a population of 32309 rabbits.

Why?

We can calculate the exponential decay using the following function:

[tex]P(t)=StartAmount*(1-\frac{percent}{100})^{t}[/tex]

Where,

Start Amount, is the starting value or amount.

Percent, is the decay rate.

t, is the time elapsed.

We are given:

[tex]StartAmount=144,000\\x=7.2(percent)\\t=2036-2016=20years[/tex]

Now, substituting it into the equation, we have:

[tex]P(t)=StartAmount(1-\frac{percent}{100})^{t}[/tex]

[tex]P(t)=144000*(1-\frac{7.2}{100})^{20}[/tex]

[tex]P(t)=144000*(1-0.072)^{20}[/tex]

[tex]P(t)=144000*(0.928)^{20}[/tex]

[tex]P(t)=144000*(0.928)^{20}[/tex]

[tex]P(t)=144000*0.861=32308.888=32309[/tex]

Hence, we have that in 2036 the population of rabbis will be 32309 rabbits.

Have a nice day!

The population of rabbits in 2036 is 32309 and this can be determined by using the exponential decay function.

Given :

  • The rabbit population of Springfield, Ohio was 144,000 in 2016.
  • It is expected to decrease by about 7.2% per year.

The formula for the exponential decay function is given by:

[tex]\rm A = P(1-\dfrac{r}{100})^t[/tex]

Now, substitute the value of known terms in the above formula.

[tex]\rm A = 144000(1-\dfrac{7.2}{100})^{20}[/tex]

Simplify the above expression.

[tex]\rm A = 144000\times (0.928)^{20}[/tex]

[tex]\rm A = 32308.888[/tex]

A [tex]\approx[/tex] 32309

So, the population of rabbits in 2036 is 32309.

For more information, refer to the link given below:

https://brainly.com/question/11154952