Given the equation rewrite the equation 28x^2+14y^2=196 in standard form, determine if the equation represents an ellipse or a hyperbola, and find the foci.

Respuesta :

the answer is...

[tex] \frac{ {x}^{2} }{7} + \frac{ {y}^{2} }{14} = 1[/tex]

The standard form of the equation of the ellipse is,[tex]\frac{x^2}{7} +\frac{y^2}{14} =1[/tex]. It is obtained by the dividing complete equation by 196.

What is the ellipse's equation?

If the major axis is a units long and the minor axis is b units long, and the ellipse is centered on (0,0). The equation for that ellipse is:

[tex]\rm \frac{x^1}{a^2} +\frac{y^2}{b^2} =1 \\\\\[/tex]

The given equation is;

28x²+14y²=196

Divide the complete equation by 196;

[tex]\rm \frac{28x^2}{196} +\frac{14y^2}{196} =\frac{196}{196} \\\\ \frac{x^2}{7} +\frac{y^2}{14} =1[/tex]

Hence, the standard form of the ellipse is represented as,[tex]\frac{x^2}{7} +\frac{y^2}{14} =1[/tex]

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