contestada

the vector [ 5,1] represent the velocity of an ultralight plane what is the direction of this vector to the nearest degree​

Respuesta :

Answer:

[tex]011\degree[/tex]

Step-by-step explanation:

The direction of a vector is given by;

[tex]\theta=\tan^{-1}(\frac{y}{x})[/tex]

The given vector is <5,1>.

The x-component of this vector is 5 and the y-component is 1.

We substitute the values into the formula to obtain;

[tex]\theta=\tan^{-1}(\frac{1}{5})[/tex]

We use our scientific calculator to obtain;

[tex]\theta=11.3099[/tex]

Therefore the direction of the given angle is [tex]011\degree[/tex] to the nearest degree.