For this case we have that by definition, the volume of a cone is given by:
[tex]V = \frac {1} {3} \pi * r ^ 2 * h[/tex]
Where:
A: It's the radio
h: It's the height
We have by the statement of the problem that:
[tex]r = 9 \ units\\h = 8 \ units[/tex]
Substituting:
[tex]V = \frac {1} {3} \pi * r ^2 * h\\V = \frac {1} {3} \pi * 9 ^ 2 * 8\\V = \frac {1} {3} \pi * 81 * 8\\V = \frac {1} {3} \pi * 648\\V = 216 \pi[/tex]
Answer:
[tex]216 \pi \ units ^ 3[/tex]
