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Identify the number of moles in 369 grams of calcium hydroxide. Use the periodic table and the polyatomic ion resource.

Respuesta :

Answer : The number of moles in 369 grams of calcium hydroxide is, 4.98 moles

Explanation : Given,

Mass of calcium hydroxide = 369 g

Molar mass of calcium hydroxide = 74.093 g/mole

Formula used :

[tex]\text{Moles of calcium hydroxide}=\frac{\text{Mass of calcium hydroxide}}{\text{Molar mass of calcium hydroxide}}[/tex]

Now put all the given values in this formula, we get the moles of calcium hydroxide.

[tex]\text{Moles of calcium hydroxide}=\frac{369g}{74.093g/mole}=4.98mole[/tex]

Therefore, the number of moles in 369 grams of calcium hydroxide is, 4.98 moles

Considering the definition of molar mass, the number of moles in 369 grams of calcium hydroxide is 4.986 moles.

What is molar mass

The molar mass of substance is a property defined as its mass per unit quantity of substance, in other words, molar mass is the amount of mass that a substance contains in one mole.

The molar mass of a compound (also called Mass or Molecular Weight) is the sum of the molar mass of the elements that form it (whose value is found in the periodic table) multiplied by the number of times they appear in the compound.

Molar mass of Ca(OH)₂

In this case, you know the molar mass of the elements is:

  • Ca= 40 g/mole
  • O= 16 g/mole
  • H= 1 g/mole

So, the molar mass of the compound Ca(OH)₂ is calculated as:

Ca(OH)₂= 40 g/mole + 2× (16 g/mole + 1 g/mole)

Solving:

Ca(OH)₂= 74 g/mole

Moles in 369 grams of Ca(OH)₂

You can apply the following rule of three: If by definition of molar mass 74 grams of Ca(OH)₂ are contained in 1 mole, 369 grams of Ca(OH)₂ are contained in how many moles?

[tex]moles of Ca(OH)_{2}= \frac{369 gramsx1mole}{74 grams}[/tex]

moles of Ca(OH)₂= 4.986 moles

The number of moles in 369 grams of calcium hydroxide is 4.986 moles.

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