Answer:
2x^2+x-4=0
x^2+\dfrac12x-2=0
x^2+\dfrac12x+\dfrac1{16}-\dfrac{33}{16}=0
\left(x+\dfrac14\right)^2=\dfrac{33}{16}
x+\dfrac14=\pm\dfrac{\sqrt{33}}4
x=\dfrac{-1\pm\sqrt{33}}4
Step-by-step explanation: lol tooooo much ∅∞
1/2 and -2 are the first answers to the question
1/16 and 1/16 are the next answers
1/4 and 33/16 are the last ones
and for the multiple choice answer which is last is A
Step-by-step explanation:
