You drop a ball from a height of 0.5 meters. Each curved path has 52% of the height of the previous path. a. Write a rule for the sequence using centimeters. The initial height is given by the term n = 1. b. What height will the ball be at the top of the sixth path?

Respuesta :

Answer:

a) [tex]a_n = 50 (0.52) ^ {n-1}[/tex]

b) [tex]a_6 = 50 (0.52) ^ 5 = 1.90\ cm[/tex]

Step-by-step explanation:

If each curved path has 52% of the previous height this means that [tex]\frac{a_{n+1}}{a_n} = 0.52[/tex]

Then the radius of convergence is 0.52 and this is a geometric series.

The geometric series have the form:

[tex]a_n = a_1 (r) ^ {n-1}[/tex]

Where

[tex]a_1[/tex] is the first term of the series and r is the radius of convergence.

In this problem

[tex]a_1 = 0.5[/tex] meters = 50 cm

[tex]r = 0.52[/tex]

a) Then the rule for the sequence is:

[tex]a_n = 50 (0.52) ^ {n-1}[/tex]

b) we must calculate [tex]a_6[/tex]

[tex]a_6 = 50 (0.52) ^ 6-1\\\\a_6 = 50 (0.52) ^ 5 = 1.90\ cm[/tex]