Answer: The required function would be [tex]x^2+3x-40[/tex]
Step-by-step explanation:
Since we have given that
There are two real zeroes :
x = -8 and x = 5
So, we need to find the function satisfying the above two zeroes:
Let α = -8 and β = 5
So, it means it is a quadratic equation :
[tex]x^2-(\alpha +\beta)x+\alpha \beta \\\\=x^2-(-8+5)x+-8\times 5\\\\=x^2+3x-40[/tex]
Hence, the required function would be [tex]x^2+3x-40[/tex]
