Answer:
D. (–3, –6) and (5, 10)
Step-by-step explanation:
The system has equations:
[tex]y=2x[/tex]...(1)
and
[tex]y=x^2-15[/tex]...(2)
Equate both equations;
[tex]x^2-15=2x[/tex]
Rewrite in standard form:
[tex]x^2-2x-15=0[/tex]
We factor to obtain:
[tex](x+3)(x-5)=0[/tex]
By the zero product principle;
[tex](x+3)=0,(x-5)=0[/tex]
[tex]\implies x=-3,x=5[/tex]
When x=-3, y=2(-3)=-6
This yields the ordered pair (-3,-6).
When x=5, y=2(5)=10
This yields the ordered pair (5,10).
The correct choice is D.