Answer:
[tex]159.2 kg/m^3[/tex]
Explanation:
The mass of the liquid is
m = 1.0 kg
The volume of the cylindrical tank is given by
[tex]V=\pi r^2 h[/tex]
where
r = 0.10 m is the radius
h = 0.20 m is the heigth
Substituting,
[tex]V=\pi (0.10 m)^2 (0.20 m)=6.28\cdot 10^{-3}m^3[/tex]
So now we can find the density of the liquid:
[tex]\rho = \frac{m}{V}=\frac{1.0 kg}{6.28\cdot 10^{-3} m^3}=159.2 kg/m^3[/tex]
