The answer is:
The heat absorbed by the iron skillet is equal to 473 Joules.
To solve the problem, we need to use the formula to calculate the quantity of heat absorbed, also, we need to remember that specific heat of the iron, which is equal to:
[tex]s=\frac{0.45J}{g*\°C }[/tex]
Where,
J, is the energy transferred.
g, is the mass of the object or substance.
°C, is the temperature measured in Celsius degrees.
We can calculate the heat absorbed using the following equation:
[tex]q=m*dT*s[/tex]
Where,
q, is the heat absorbed
m, is the mass of the object
dT, is the change in temperature
s, is the specific heat of the substance.
We are given the following information:
[tex]mass=70g\\dT=28\°C-13\°C=15\°C\\s=\frac{0.45J}{g*\°C }[/tex]
So, substituting and calculating, we have:
[tex]q=m*dT*s[/tex]
[tex]q=70g*15\°C*\frac{0.45J}{g*\°C }=472.5J=473J[/tex]
Hence, the heat absorbed is equal to 473 Joules.
Have a nice day!
