Answer:
[tex]3,744.45\ m^{2}[/tex]
Step-by-step explanation:
we know that
The area of a sector is equal to
[tex]A=\frac{\theta}{360\°}\pi r^{2}[/tex]
where
[tex]\theta[/tex] ------> is the angle in degrees
r is the radius of the circle
In this problem we have
[tex]r=45\ m[/tex]
[tex]\theta=212\°[/tex]
assume
[tex]\pi =3.14[/tex]
substitute the values
[tex]A=\frac{212\°}{360\°}(3.14)(45)^{2}[/tex]
[tex]A=3,744.45\ m^{2}[/tex]
