Answer:
The vertex that maximize the problem is (2,000,4,000)
Step-by-step explanation:
we have
[tex]z=10x+6y[/tex]
The vertex of the shaded region are
A(0,0), B(4,000,0),C(2,000,4,000), D(0,6,000)
Substitute the value of x and the value of y of each vertex in the z equation to find the solution
case A) A(0,0)
[tex]z=10(0)+6(0)=0[/tex]
case B) B(4,000,0)
[tex]z=10(4,000)+6(0)=40,000[/tex]
case C) C(2,000,4,000)
[tex]z=10(2,000)+6(4,000)=44,000[/tex]
case D) D(0,6,000)
[tex]z=10(0)+6(6,000)=36,000[/tex]
therefore
The vertex that maximize the problem is (2,000,4,000)