Ytterbium decays 50% every 4.2 days. How much of an 80g sample would be left after 54.6 days? Use exponential decay formula.
A. 67 g
B. 53,211.33 g
C.41.76 g
D. 9.80 g
E. 0.12 g

Respuesta :

Answer: Option E

[tex]0.120\ g[/tex]

Step-by-step explanation:

The exponential decay formula is:

[tex]C (t) = pe^ {-rt}[/tex]

Where p is the initial amount of Ytterbium

r is the rate of decrease

C(t) is the amount of Ytterbium in grams as a function of time

t is the time in days

In this problem:

[tex]p = 80\ g\\\\r=\frac{50\%}{100\%}\\\\r=0.5[/tex]

t is the time in units of 4.2 days

Then

[tex]C(t) = 80e^{-0.5t}[/tex]

We want to calculate the amount of Ytterbium in 54.6 days.

Then as t is the time in units of 4.2 days

[tex]t = \frac{54.6}{4.2} = 13\\\\t = 13[/tex]

Finally

[tex]C(t=13) = 80e^{-0.5*13}[/tex]

[tex]C(t) = 0.120\ g[/tex]