Answer: [tex]x_1=3\\x_2=-5[/tex]
Step-by-step explanation:
Divide boht sides of the eqeuation by 9:
[tex]\frac{9(x+1)^2}{9}=\frac{144}{9}\\\\(x+1)^2=16[/tex]
Remembert that:
[tex](a+b)^2=a^2+2ab+b^2[/tex]
Then, applying this, you get:
[tex]x^2+2(x)(1)+1^2=16\\x^2+2x+1=16[/tex]
Subtract 16 from both sides:
[tex]x^2+2x+1-16=16-16\\x^2+2x-15=0[/tex]
Factor the quadratic equation. Find two numbers whose sum be 2 and whose product be -15, then:
[tex](x-3)(x+5)=0\\x_1=3\\x_2=-5[/tex]
