Keisha is solving the equation 7 to the power of x equals 9. Which equation shows the first step she should take?

Question 4 options:

log 7 to the power of x equals log 9

log 7 to the power of x equals 9

7 x equals log 9

log 7 to the power of x equals ln 9


Mary is solving the equation 2 to the power of n end power minus 3 equals 83. Her first three steps are shown:

Step 1: 2 to the power of n end power minus 3 equals 83
Step 2: 2 to the power of n equals 86
Step 3: ln 2 to the power of n end power equals ln 86

Which equation could be Step 4?

Question 5 options:
n equals ln 86 minus ln 2

ln 2 equals n ln 86

n plus ln 2 equals ln 86

n ln 2 equals ln 86

What is the exact solution of 2 e to the power of x equals 14?

Question 6 options:

ln 7

ln 12

2 ln 14

2 ln 7

Respuesta :

Answer:

The correct answers are:

Question 4: the first step Keisha should take is: log to the power of x equals log 9.

Question 5: step 4 could be n ln 2 equals ln 86

Question 6: the exact solution is x=ln(7)

Step-by-step explanation:

Ok,

Question 4: the equation that shows the first step Keisha should take is:

[tex]7^{x}=9[/tex]

[tex]log(7^{x} )=log(9)[/tex]

[tex]x(log(7))=log(9)[/tex] (applying the properties of logarithms)

[tex]x=\frac{log(9)}{log(7)} =1.129[/tex]

Solution: the first step Keisha should take is: log to the power of x equals log 9.

Question 5: Her first three steps are:

[tex]2^{n}-3=83[/tex]

[tex]2^{n}-3+3=83+3[/tex] (adding 3 to both sides)

[tex]2^{n}=86[/tex]

[tex]2^{n}-3+3=83+3[/tex]

[tex]nln(2)=ln(86)[/tex]

Solution: step 4 is: [tex]nln(2)=ln(86)[/tex] (applying the properties of logarithms)

Question 6: The exact solution of 2 e to the power of x equals 14 is:

[tex]2e^{x}=14[/tex]

[tex]\frac{2e^{x} }{2} =\frac{14}{2}[/tex] (dividing both sides by 2)

[tex]e^{x}=7[/tex]

[tex]xln(e)=ln7[/tex] (ln(e)=1)

[tex]x=ln(7)[/tex]

Solution: [tex]x=ln(7)[/tex]