Answer:
Add 225/4 to x^2 + 15x.
Step-by-step explanation:
Take the coefficient of the middle term, 15.
Now divide it by 2, 15/2.
Square that, 225/4.
Add 225/4 to x^2 + 15x.
To create a perfect square, add 225/4 in the quadratic function x²+ 15x.
Any equation of the form [tex]\rm ax^2+bx+c=0[/tex] Where x is variable and a, b, and c are any real numbers where a ≠ 0 is called a quadratic equation.
As we know, the formula for the roots of the quadratic equation is given by:
[tex]\rm x = \dfrac{-b \pm\sqrt{b^2-4ac}}{2a}[/tex]
We have a quadratic function:
= x²+ 15x
To create a perfect square, add and subtract by 225/4
= x²+ 15x + 225/4 - 225/4
= x²+ 15x + 15²/2² - 225/4
= (x + 15/2)² - 225/4
Thus, to create a perfect square, add 225/4 in the quadratic function x²+ 15x.
Learn more about quadratic equations here:
brainly.com/question/2263981
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