find the magnitude and direction angle for the vector v = 5 cos 144°j
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Answer:
5, 144°
Step-by-step explanation:
A vector with magnitude v and angle θ can be split into x and y components as:
vx = v cos θ
vy = v sin θ
Here, we're given the components and asked to find the magnitude and direction. By matching, we can see the magnitude is 5 and the angle is 144°.
So the answer is 5, 144°.
Answer: I just took the test and got 100%
1. C, The vector will not change direction but will increase in magnitude.
2. C, 56 ft lbs
3. C, (-2,-3)
4. A, u = -4 sqrt 41/41 i - 5 sqrt 41/41 j
5. A, 56
6. C, 11.4 ft/sec
7. Do not copy my exact answer please (: They are equal. You know because if you take the points of each segment and subtract them, you will get the same points for both segments.
8a. A, (-10,-16)
8b. D, 2 sqrt 89
9a. C, (-14,-21)
9b. B, 7 sqrt 13
10a. C, (-18,-26)
10b. B, 10 sqrt 10
11. B, 5,144 degrees
12. A, 173 degrees
13. C, (1/6, -1/5)
14. D, 163 mph
15. C, 10j
16. D, 2 sqrt 3
17. A, 98.1 degrees
18. Do not copy my exact answer please (: The angle between the two vectors is 26.75 degrees.
Feel free to mark as brainliest (: