Answer:
Two distinct real solutions.
Step-by-step explanation:
Given the equation in the form [tex]ax^2+bx+c=0[/tex], you need to find the Discriminant with this formula:
[tex]D=b^2-4ac[/tex]
For the equation [tex]-2x^2+5x-3=0[/tex] you can identify that:
[tex]a=-2\\b=5\\c=-3[/tex]
Then, substituting these values into the formula, you get that the Discriminant is:
[tex]D=5^2-4(-2)(-3)[/tex]
[tex]D=1[/tex]
Since [tex]D>0[/tex], then [tex]-2x^2+5x-3=0[/tex] has two distinct real solutions.
