Answer:
0.1612 mol.
Explanation:
- From the balanced equation:
2Ca₃(PO₄)₂ + 6SiO₂ + 10C → 6CaSiO₃ + P₄ + 10CO.
2.0 moles of Ca₃(PO₄)₂ react with sufficient SiO₂ and C to produce 1.0 mole of P₄ and other products.
- we need to calculate the no. of moles of 100.0 g of Ca₃(PO₄)₂:
no. of moles of Ca₃(PO₄)₂ = mass / molar mass = (100.0 g)/(310.18 g/mol) = 0.3224 mol.
Using cross-multiplication:
2.0 moles of Ca₃(PO₄)₂ produce → 1.0 mole of P₄.
0.3224 mole of Ca₃(PO₄)₂ produce → ??? mole of P₄.
∴ The no. of moles of phosphorous (P₄) will be produced = (1.0 mole)(0.3224 mole)/(2.0 mole) = 0.1612 mol.
