Answer: Third option
[tex]f(x) - 2[/tex]
Step-by-step explanation:
The function [tex]y=log_3 (x)[/tex] passes through the point (1,0) since the function [tex]y=log_a (x)[/tex] always cuts the x-axis at [tex]x = 1[/tex].
Then, if the transformed function passes through point (1,-2) then this means that the graph of [tex]y=log_3(x)[/tex] was moved vertically 2 units down.
The transformation that displaces the graphically of a function k units downwards is:
[tex]y = f (x) + k[/tex]
Where k is a negative number. In this case [tex]k = -2[/tex]
Then the transformation is:
[tex]f(x) -2[/tex]
and the transformed function is:
[tex]y = log_3 (x) -2[/tex]