How do I solve for f of f
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Answer:
[tex]\large\boxed{(F\circ F)(n)=4n+6}[/tex]
Step-by-step explanation:
[tex]F(n)=2n+2\\\\(F\circ F)(n)\to\text{Replace n with 2n + 2 in F(n)}:\\\\(F\circ F)(n)=2(2n+2)+2\qquad\text{use the distributive property}\\\\(F\circ F)(n)=(2)(2n)+(2)(2)+2=4n+4+2=4n+6[/tex]