Answer:
3. +3.09 kJ
Explanation:
The change in internal energy of the gas is given by the 1st law of thermodynamics:
[tex]\Delta U=Q-W[/tex]
where
Q is the heat transferred to the gas
W is the work done by the gas
Here we have:
[tex]Q=+4.00 kJ[/tex] is the amount of heat transferred to the nitrogen
[tex]p=3.00 atm = 3.03\cdot 10^5 Pa[/tex] is the pressure of the gas
[tex]\Delta V=4.00 L-1.00 L=3.00 L = 0.003 m^3[/tex] is the change in volume of the gas
So the work done by the gas is
[tex]W=p\Delta V=(3.03\cdot 10^5 Pa)(0.003 m^3)=909 J = 0.91 kJ[/tex]
So, the change in internal energy of the gas is
[tex]\Delta U=4.00 kJ-0.91 kJ=+3.09 kJ[/tex]
