The right question is
b.) If the pendulum is carried to the moon where the acceleration of gravity is around g / 6, what is the current period?
A simple pendulum consists of a light string and a small ball (pendulum ball) with mass m hanging from the end of the rope. In analyzing the movement of a simple pendulum, the air friction force is ignored and the mass of the rope is so small that it can be ignored relative to the ball.
A simple pendulum consisting of a rope with a length L and a pendulum ball with mass m. The forces acting on the pendulum ball are the weight force (w = mg) and the FT string tension force. Gravity has a component of mg cos theta which is in the direction of the rope and mg sin theta which is perpendicular to the rope. The pendulum oscillates due to the presence of mg sin theta gravity component. Because there is no air friction, the pendulum oscillates along a circular arc with the same amplitude.
The requirement for an object to do Simple Harmonic Motion is if the recovery force is proportional to the deviation. If the recovery force is proportional to the deviation of x or the angle of the theta, the pendulum performs Simple Harmonic Motion.
The simple pendulum period can be determined using the equation:
T = 2n (sqrt m / k
We replace the effective force constant with mg / L
T = 2n (sqrt m / (mg / L))
T = 2n (sqrt L / g -> 0 small)
Simple Pendulum Frequency
f = 1 / T
f = 1 / 2n (sqrt L / g)
f = (1 / 2n) (sqrt g / L -> 0 small)
This is a simple pendulum frequency equation
Information :
T is the period, f is the frequency, L is the length of the rope and g is the acceleration due to gravity.
Learn More
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Detail
Class: High School
Subject: Physics
Keywords: pendulum, simple, formula
